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| // Elimination | |
| // Solution by Jacob Plachta | |
| using namespace std; | |
| template<typename T> T Abs(T x) { return(x < 0 ? -x : x); } | |
| template<typename T> T Sqr(T x) { return(x * x); } | |
| string plural(string s) { return(Sz(s) && s[Sz(s) - 1] == 'x' ? s + "en" : s + "s"); } | |
| const int INF = (int)1e9; | |
| const LD EPS = 1e-12; | |
| const LD PI = acos(-1.0); | |
| // dyn[b][w] = expected number of remaining rounds | |
| // when there are b better and w worse players than you | |
| LD dyn[LIM][LIM]; | |
| int NumPairs(int c) | |
| { | |
| return(c * (c - 1) / 2); | |
| } | |
| // inv indicates that b/w have been swapped to capture worse players winning | |
| LD Comp(int b, int w, bool inv) | |
| { | |
| LD p = (LD)1 / NumPairs(b + w + 1), d = 0; | |
| // elimination of better player than you | |
| if (b > 0) | |
| d += NumPairs(b) * p * (inv ? dyn[w][b - 1] : dyn[b - 1][w]); | |
| // elimination of worse player than you | |
| if (w > 0) | |
| d += (w * (b + 1) + NumPairs(w)) * p * (inv ? dyn[w - 1][b] : dyn[b][w - 1]); | |
| return(d); | |
| } | |
| void ProcessCase() | |
| { | |
| int N, i, b, w; | |
| LD P; | |
| // input | |
| scanf("%d%Lf", &N, &P); | |
| // DP | |
| Fill(dyn, 0); | |
| Fox(b, N) | |
| { | |
| Fox(w, N - b) | |
| { | |
| if (b + w) | |
| { | |
| dyn[b][w] = 1 + | |
| Comp(b, w, false) * P + // better players winning | |
| Comp(w, b, true) * (1 - P); // worse players winning | |
| } | |
| } | |
| } | |
| // output | |
| Fox(i, N) | |
| printf("%.8Lf\n", dyn[N - i - 1][i]); | |
| } | |
| int main() | |
| { | |
| int T, t; | |
| scanf("%d\n", &T); | |
| Fox1(t, T) | |
| { | |
| printf("Case #%d:\n", t); | |
| ProcessCase(); | |
| } | |
| return(0); | |
| } |